Add investment_optimization.py exercise

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Ivan Malison 2018-04-04 00:04:57 -07:00
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#!/usr/bin/env python
import heapq
from collections import namedtuple
BuyOpportunity = namedtuple(
'BuyOpportunity',
['trans_yield', 'start', 'end']
)
def maximize_profit(num_transactions, prices):
minima, maxima = find_extrema(prices)
opp_queue, reverse_opp_queue = make_opportunity_queues(
minima, maxima, prices,
)
if not opp_queue:
return []
largest_segment = opp_queue[0][1]
# Segments will be kept in sorted order
segments = [largest_segment]
# Remove any reverse yields that are greater than the largest actual yield
# since they can never be realized anyway.
while (reverse_opp_queue and reverse_opp_queue[0][1].trans_yield >=
largest_segment.trans_yield):
heapq.heappop(reverse_opp_queue)
def try_rev_opp():
# It is okay to definitely pop here even though we don't know that we
# can actually use the opp for the following reason:
# Since the rev opp queue was selected OVER that of the opp queue, we
# KNOW that the bounding segment that includes this rev opp must have
# already been selected if it is going to be included at all (since it
# must have greater yield).
_, rev_opp_can = heapq.heappop(reverse_opp_queue)
for (seg_index, split_seg) in enumerate(segments):
if split_seg.end >= rev_opp_can.end:
# Since segments is sorted, this must be the correct segment
break
else:
return
if split_seg.start <= rev_opp_can.start:
# We found the containing segment
left_yield = prices[rev_opp_can.start] - prices[split_seg.start]
right_yield = prices[split_seg.end] - prices[rev_opp_can.end]
left_segment = BuyOpportunity(left_yield, split_seg.start, rev_opp_can.start)
right_segment = BuyOpportunity(right_yield, rev_opp_can.end, split_seg.end)
segments.pop(seg_index)
segments.insert(seg_index, left_segment)
segments.insert(seg_index + 1, right_segment)
def try_opp():
_, opp = heapq.heappop(opp_queue)
if not segments:
segments.append(opp)
insertion_index = 0
for (index, seg) in enumerate(segments):
if seg.start >= opp.start:
insertion_index = index
break
else:
insertion_index = len(segments)
seg = None
previous_seg = segments[insertion_index - 1] if insertion_index > 0 else None
if ((seg is None or seg.start >= opp.end) and
(previous_seg is None or previous_seg.end <= opp.start)):
# There is no overlap, so we can insert
segments.insert(insertion_index, opp)
else:
pass
while (opp_queue or reverse_opp_queue) and len(segments) < num_transactions:
if not reverse_opp_queue:
try_opp()
elif not opp_queue:
try_rev_opp()
else:
opp_can = opp_queue[0][1]
rev_opp_can = reverse_opp_queue[0][1]
if rev_opp_can.trans_yield > opp_can.trans_yield:
try_rev_opp()
else:
try_opp()
return segments
def make_opportunity_queues(minima, maxima, prices):
opp_queue = []
reverse_opp_queue = []
for min_index, minimum in enumerate(minima):
for max_index, maximum in enumerate(maxima):
transaction_yield = prices[maximum] - prices[minimum]
if transaction_yield < 0:
# We can ignore this pair because the transaction has negative
# yield.
continue
# minimum comes before maximum in time
if minimum < maximum:
# Transaction yield is made negative because heapq is a min-heap
heapq.heappush(
opp_queue, ((-transaction_yield, maximum - minimum), BuyOpportunity(
transaction_yield, minimum, maximum,
)),
)
else:
heapq.heappush(
reverse_opp_queue, (-transaction_yield, BuyOpportunity(
transaction_yield, maximum, minimum,
))
)
return opp_queue, reverse_opp_queue
def find_extrema(prices):
maxima = []
minima = []
length_of_prices = len(prices)
if length_of_prices < 2:
return minima, maxima
upwards = None
last = prices[0]
for (index, price) in enumerate(prices):
if price < last:
if upwards is True:
maxima.append(index - 1)
elif upwards is None:
# We set the starting price as a maximum, but theres no point
# since we would really never buy.
maxima.append(0)
pass
upwards = False
elif price > last:
if upwards is False:
minima.append(index - 1)
elif upwards is None:
# The starting value is a minimum
minima.append(0)
upwards = True
last = price
if upwards is True:
maxima.append(length_of_prices - 1)
elif upwards is False:
minima.append(length_of_prices - 1)
return minima, maxima
if __name__ == '__main__':
print (maximize_profit(10, [0, 1, 3, 2, 3, 0, 10, 12, 1, 2, 3, 2, 0, 2, 4, 3, 6, 4, 14, 1, 0, 2, 4, 5, 4, 5, 6]))
print [
BuyOpportunity(trans_yield=1, start=0, end=1),
BuyOpportunity(trans_yield=12, start=2, end=4),
BuyOpportunity(trans_yield=2, start=5, end=7),
BuyOpportunity(trans_yield=6, start=9, end=11),
BuyOpportunity(trans_yield=6, start=12, end=13),
BuyOpportunity(trans_yield=10, start=14, end=15),
BuyOpportunity(trans_yield=5, start=17, end=20),
BuyOpportunity(trans_yield=2, start=21, end=23),
]